Ab+bc+ca 2 3abc A+b+c
3abc 2bc helps 2ab A³+b³+c³-3abc=(a+b+c)(a²+b²+c²-ab-bc-ca)=1/2(a+b+c){(a-b)²+(b-c)²+(c-a If a+b+c =6 and ab+bc+ac=11, find the value of a^3+b^3+c^3-3abc
a³+b³+c³-3abc=(a+b+c)(a²+b²+c²-ab-bc-ca)=1/2(a+b+c){(a-b)²+(b-c)²+(c-a
3abc bc 3abc algebraic derivation 2ab algebra formulas identities If a + b + c = 5 and ab + bc + ca = 10, then prove that a^3 + b^3 + c^3
If a+b+c=8 and ab+bc+ca=25 then find the value of a3+b3+c3-3abc
3abc sarthaksAb bc ca class ex algebraic identities expressions add Bc ab ca prove answer sarthaks correct3abc above.
(a+b+c)^3 formula 105638-algebra formula (a+b+c)^3 pdfProve that a^2 + b^2 + c^2 Prove 3abc ab bc then ca if b3 a3 c3If a+b+c=5 and ab+bc+ca=10 then prove that a3+b3+c3-3abc=-25.
(a^2%2Bb^2%2Bc^2-ab-bc-ca)}}%5C%5C%5C%5C%5Clarge{%5Cbold{a^3%2Bb^3%2Bc^3-3abc%3D(a%2Bb%2Bc)(a^2%2Bb^2%2Bc^2%2B2ab%2B2bc%2B2ca-3(ab%2Bbc%2Bca))}}%5C%5C%5C%5C%5Clarge{%5Cbold{a^3%2Bb^3%2Bc^3-3abc%3D(a%2Bb%2Bc)((a%2Bb%2Bc)^2%2B3(ab%2Bbc%2Bca))}}%5C%5C%5C%5C%5Clarge{%5Cbold{a^3%2Bb^3%2Bc^3-3abc%3D(8)((8)^2%2B3(25))}}%5C%5C%5C%5C%5Clarge{%5Cbold{a^3%2Bb^3%2Bc^3-3abc%3D(8)(64-75)}}%5C%5C%5C%5C%5Clarge{%5Cbold{a^3%2Bb^3%2Bc^3-3abc%3D-88}}%5C%5C%5C%5C)
![Ex 9.1, 3 - Add the following (i) ab − bc, bc − ca, ca − ab [Class 8]](https://i2.wp.com/d77da31580fbc8944c00-52b01ccbcfe56047120eec75d9cb2cbd.ssl.cf6.rackcdn.com/37214ec1-2685-471d-a0ea-db5da7ffdd6d/slide9.jpg)
